Regular Expression to get a string between parentheses in Golang

Example

package main

import (
	"fmt"
	"regexp"
	"strings"
)

func main() {
	str1 := "This is a (sample) ((string)) with (SOME) special words"

	re := regexp.MustCompile(`\((.*?)\)`)
	fmt.Printf("Pattern: %v\n", re.String()) // print pattern

	fmt.Println("\nText between parentheses:")
	submatchall := re.FindAllString(str1, -1)
	for _, element := range submatchall {
		element = strings.Trim(element, "(")
		element = strings.Trim(element, ")")
		fmt.Println(element)
	}
}

Output

Pattern: \((.*?)\)
Text between parentheses:
sample
string
SOME

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Regular Expression to get a string between parentheses in Golang

Example

Output

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Most Helpful This Week