Golang import function from another folder?

├── employee
│   ├── go.mod
│   ├── main.go
│   └── basic
│       └── basic.go
│       └── gross
│       	└── gross.go

Go inside the employee directory and run the following command to create a go module named employee.

go mod init employee

The above command will create a file named go.mod. The following will be the contents of the file.

module employee

go 1.14

To use a custom package we must import it first. The import path is the name of the module appended by the subdirectory of the package and the package name. In our example the module name is employee and the package basic is in the basic folder directly under employee folder. Moreover, the package gross is in the gross folder which is under basic folder.

Hence, the line import "employee/basic" will import the basic package, and "employee/basic/gross" will import the gross package

package main

import (
	b "employee/basic"
	"employee/basic/gross"

	"fmt"
)

func main() {
	b.Basic = 10000
	fmt.Println(gross.GrossSalary())
}

We are aliasing the basic package as b. We called GrossSalary function of gross package and assigned value to Basic variable of basic package.

Create a file basic.go inside the basic folder. The file inside the basic folder should start with the line package basic as it belongs to the basic package.

package basic

var hra int = 5
var tax int = 2
var Basic int

func Calculation() (allowance int, deduction int) {
	allowance = (Basic * hra) / 100
	deduction = (Basic * tax) / 100
	return
}

Create a file gross.go inside the gross folder. The file inside the gross folder should start with the line package gross as it belongs to the gross package.

package gross

import (
	b "employee/basic"
)

func GrossSalary() int {
	a, t := b.Calculation()
	return ((b.Basic + a) - t)
}

The function GrossSalary call the function Calculation of basic package. We are aliasing the basic package as b.

If you run the program, you will get the following output.

10300